1134214031113 has 4 divisors (see below), whose sum is σ = 1160591101648. Its totient is φ = 1107836960580.

The previous prime is 1134214031081. The next prime is 1134214031131. The reversal of 1134214031113 is 3111304124311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1134214031113 - 2⁵ = 1134214031081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1134214037113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13188535203 + ... + 13188535288.

It is an arithmetic number, because the mean of its divisors is an integer number (290147775412).

Almost surely, 2^{1134214031113} is an apocalyptic number.

It is an amenable number.

1134214031113 is a deficient number, since it is larger than the sum of its proper divisors (26377070535).

1134214031113 is an equidigital number, since it uses as much as digits as its factorization.

1134214031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26377070534.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1134214031113 its reverse (3111304124311), we get a palindrome (4245518155424).

The spelling of 1134214031113 in words is "one trillion, one hundred thirty-four billion, two hundred fourteen million, thirty-one thousand, one hundred thirteen".