Base | Representation |
---|---|
bin | 11001110010100000101010… |
… | …100010011001000100001011 |
3 | 112212121001112211102220111221 |
4 | 121302200222202121010023 |
5 | 104331302141230331103 |
6 | 1041121235521102511 |
7 | 32614325045615536 |
oct | 3162405242310413 |
9 | 485531484386457 |
10 | 113422210011403 |
11 | 3315a0a8705597 |
12 | 10879b98787a37 |
13 | 4b3988c942777 |
14 | 2001942a07a1d |
15 | d1a58a6141bd |
hex | 67282a89910b |
113422210011403 has 2 divisors, whose sum is σ = 113422210011404. Its totient is φ = 113422210011402.
The previous prime is 113422210011389. The next prime is 113422210011449. The reversal of 113422210011403 is 304110012224311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113422210011403 - 229 = 113421673140491 is a prime.
It is not a weakly prime, because it can be changed into another prime (113422210011703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56711105005701 + 56711105005702.
It is an arithmetic number, because the mean of its divisors is an integer number (56711105005702).
Almost surely, 2113422210011403 is an apocalyptic number.
113422210011403 is a deficient number, since it is larger than the sum of its proper divisors (1).
113422210011403 is an equidigital number, since it uses as much as digits as its factorization.
113422210011403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 113422210011403 its reverse (304110012224311), we get a palindrome (417532222235714).
The spelling of 113422210011403 in words is "one hundred thirteen trillion, four hundred twenty-two billion, two hundred ten million, eleven thousand, four hundred three".
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