Base | Representation |
---|---|
bin | 10101001000000110… |
… | …01001010001100001 |
3 | 1002021110101121011100 |
4 | 22210003021101201 |
5 | 141212102104213 |
6 | 5113251105013 |
7 | 551033204613 |
oct | 124403112141 |
9 | 32243347140 |
10 | 11342222433 |
11 | 48a0430653 |
12 | 22465a2169 |
13 | 10b9ab9729 |
14 | 798514db3 |
15 | 465b3d773 |
hex | 2a40c9461 |
11342222433 has 24 divisors (see below), whose sum is σ = 16931882240. Its totient is φ = 7308830880.
The previous prime is 11342222429. The next prime is 11342222447. The reversal of 11342222433 is 33422224311.
11342222433 is a `hidden beast` number, since 1 + 1 + 3 + 4 + 2 + 222 + 433 = 666.
It is not a de Polignac number, because 11342222433 - 22 = 11342222429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11342222397 and 11342222406.
It is not an unprimeable number, because it can be changed into a prime (11342222933) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 214158 + ... + 261816.
Almost surely, 211342222433 is an apocalyptic number.
It is an amenable number.
11342222433 is a deficient number, since it is larger than the sum of its proper divisors (5589659807).
11342222433 is a wasteful number, since it uses less digits than its factorization.
11342222433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48549 (or 48546 counting only the distinct ones).
The product of its digits is 6912, while the sum is 27.
Adding to 11342222433 its reverse (33422224311), we get a palindrome (44764446744).
The spelling of 11342222433 in words is "eleven billion, three hundred forty-two million, two hundred twenty-two thousand, four hundred thirty-three".
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