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1134303441113 = 3389334701517
BaseRepresentation
bin10000100000011001110…
…000001111000011011001
311000102211120001010111202
4100200121300033003121
5122041023140103423
62225031455203545
7144644045110643
oct20403160170331
94012746033452
101134303441113
113a80677a3027
12163a03b165b5
1382c6c8c5c1b
143cc87293893
151e78c2dd728
hex10819c0f0d9

1134303441113 has 4 divisors (see below), whose sum is σ = 1134638146020. Its totient is φ = 1133968736208.

The previous prime is 1134303441079. The next prime is 1134303441211. The reversal of 1134303441113 is 3111443034311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 966000019609 + 168303421504 = 982853^2 + 410248^2 .

It is a cyclic number.

It is not a de Polignac number, because 1134303441113 - 28 = 1134303440857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1134303461113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167347370 + ... + 167354147.

It is an arithmetic number, because the mean of its divisors is an integer number (283659536505).

Almost surely, 21134303441113 is an apocalyptic number.

It is an amenable number.

1134303441113 is a deficient number, since it is larger than the sum of its proper divisors (334704907).

1134303441113 is an equidigital number, since it uses as much as digits as its factorization.

1134303441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 334704906.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1134303441113 its reverse (3111443034311), we get a palindrome (4245746475424).

The spelling of 1134303441113 in words is "one trillion, one hundred thirty-four billion, three hundred three million, four hundred forty-one thousand, one hundred thirteen".

Divisors: 1 3389 334701517 1134303441113