Base | Representation |
---|---|
bin | 10000100000011010010… |
… | …001010100011111001001 |
3 | 11000102212011100202122021 |
4 | 100200122101110133021 |
5 | 122041032400122441 |
6 | 2225032405124441 |
7 | 144644211612454 |
oct | 20403221243711 |
9 | 4012764322567 |
10 | 1134312114121 |
11 | 3a80716871aa |
12 | 163a069b9721 |
13 | 82c71641794 |
14 | 3cc884b049b |
15 | 1e78ce533d1 |
hex | 1081a4547c9 |
1134312114121 has 2 divisors, whose sum is σ = 1134312114122. Its totient is φ = 1134312114120.
The previous prime is 1134312114073. The next prime is 1134312114193. The reversal of 1134312114121 is 1214112134311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 902889542025 + 231422572096 = 950205^2 + 481064^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134312114121 - 27 = 1134312113993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134312114421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567156057060 + 567156057061.
It is an arithmetic number, because the mean of its divisors is an integer number (567156057061).
Almost surely, 21134312114121 is an apocalyptic number.
It is an amenable number.
1134312114121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134312114121 is an equidigital number, since it uses as much as digits as its factorization.
1134312114121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 25.
Adding to 1134312114121 its reverse (1214112134311), we get a palindrome (2348424248432).
The spelling of 1134312114121 in words is "one trillion, one hundred thirty-four billion, three hundred twelve million, one hundred fourteen thousand, one hundred twenty-one".
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