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1134312212203 = 1550697314887
BaseRepresentation
bin10000100000011010010…
…001101100011011101011
311000102212011112202011221
4100200122101230123223
5122041032411242303
62225032411202511
7144644212501432
oct20403221543353
94012764482157
101134312212203
113a8071743965
12163a06a46437
1382c71677311
143cc884d8119
151e78ce724bd
hex1081a46c6eb

1134312212203 has 4 divisors (see below), whose sum is σ = 1134319682160. Its totient is φ = 1134304742248.

The previous prime is 1134312212171. The next prime is 1134312212227. The reversal of 1134312212203 is 3022122134311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134312212203 - 25 = 1134312212171 is a prime.

It is a super-2 number, since 2×11343122122032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1134312212263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3502375 + ... + 3812512.

It is an arithmetic number, because the mean of its divisors is an integer number (283579920540).

Almost surely, 21134312212203 is an apocalyptic number.

1134312212203 is a deficient number, since it is larger than the sum of its proper divisors (7469957).

1134312212203 is an equidigital number, since it uses as much as digits as its factorization.

1134312212203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7469956.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1134312212203 its reverse (3022122134311), we get a palindrome (4156434346514).

The spelling of 1134312212203 in words is "one trillion, one hundred thirty-four billion, three hundred twelve million, two hundred twelve thousand, two hundred three".

Divisors: 1 155069 7314887 1134312212203