Base | Representation |
---|---|
bin | 110100110100100001… |
… | …0011101111001100101 |
3 | 101211210020012100221001 |
4 | 1221221002131321211 |
5 | 3324301414413013 |
6 | 124035404353301 |
7 | 11123636012065 |
oct | 1515102357145 |
9 | 354706170831 |
10 | 113431404133 |
11 | 441190858a3 |
12 | 19b97b45831 |
13 | a909399b58 |
14 | 56c0c073a5 |
15 | 2e3d4a4ddd |
hex | 1a6909de65 |
113431404133 has 32 divisors (see below), whose sum is σ = 119807880192. Its totient is φ = 107270217600.
The previous prime is 113431404131. The next prime is 113431404139. The reversal of 113431404133 is 331404134311.
It is a cyclic number.
It is not a de Polignac number, because 113431404133 - 21 = 113431404131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113431404131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 242893566 + ... + 242894032.
It is an arithmetic number, because the mean of its divisors is an integer number (3743996256).
Almost surely, 2113431404133 is an apocalyptic number.
It is an amenable number.
113431404133 is a deficient number, since it is larger than the sum of its proper divisors (6376476059).
113431404133 is a wasteful number, since it uses less digits than its factorization.
113431404133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1305.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 113431404133 its reverse (331404134311), we get a palindrome (444835538444).
The spelling of 113431404133 in words is "one hundred thirteen billion, four hundred thirty-one million, four hundred four thousand, one hundred thirty-three".
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