Base | Representation |
---|---|
bin | 10000100000011010101… |
… | …111110100110110110011 |
3 | 11000102212201102001022222 |
4 | 100200122233310312303 |
5 | 122041041422023102 |
6 | 2225033252351255 |
7 | 144644336600165 |
oct | 20403257646663 |
9 | 4012781361288 |
10 | 1134320111027 |
11 | 3a8076149414 |
12 | 163a0961552b |
13 | 82c731b168c |
14 | 3cc89592935 |
15 | 1e78d9d2aa2 |
hex | 1081abf4db3 |
1134320111027 has 2 divisors, whose sum is σ = 1134320111028. Its totient is φ = 1134320111026.
The previous prime is 1134320110921. The next prime is 1134320111033. The reversal of 1134320111027 is 7201110234311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1134320111027 - 210 = 1134320110003 is a prime.
It is a super-2 number, since 2×11343201110272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1134320110987 and 1134320111005.
It is not a weakly prime, because it can be changed into another prime (1134320111527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567160055513 + 567160055514.
It is an arithmetic number, because the mean of its divisors is an integer number (567160055514).
Almost surely, 21134320111027 is an apocalyptic number.
1134320111027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134320111027 is an equidigital number, since it uses as much as digits as its factorization.
1134320111027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 1134320111027 its reverse (7201110234311), we get a palindrome (8335430345338).
The spelling of 1134320111027 in words is "one trillion, one hundred thirty-four billion, three hundred twenty million, one hundred eleven thousand, twenty-seven".
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