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1134320111027 is a prime number
BaseRepresentation
bin10000100000011010101…
…111110100110110110011
311000102212201102001022222
4100200122233310312303
5122041041422023102
62225033252351255
7144644336600165
oct20403257646663
94012781361288
101134320111027
113a8076149414
12163a0961552b
1382c731b168c
143cc89592935
151e78d9d2aa2
hex1081abf4db3

1134320111027 has 2 divisors, whose sum is σ = 1134320111028. Its totient is φ = 1134320111026.

The previous prime is 1134320110921. The next prime is 1134320111033. The reversal of 1134320111027 is 7201110234311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1134320111027 - 210 = 1134320110003 is a prime.

It is a super-2 number, since 2×11343201110272 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1134320110987 and 1134320111005.

It is not a weakly prime, because it can be changed into another prime (1134320111527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567160055513 + 567160055514.

It is an arithmetic number, because the mean of its divisors is an integer number (567160055514).

Almost surely, 21134320111027 is an apocalyptic number.

1134320111027 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134320111027 is an equidigital number, since it uses as much as digits as its factorization.

1134320111027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 1134320111027 its reverse (7201110234311), we get a palindrome (8335430345338).

The spelling of 1134320111027 in words is "one trillion, one hundred thirty-four billion, three hundred twenty million, one hundred eleven thousand, twenty-seven".