Base | Representation |
---|---|
bin | 10000100000011010111… |
… | …100100001101000101001 |
3 | 11000102212221200012001112 |
4 | 100200122330201220221 |
5 | 122041043300041134 |
6 | 2225033452000105 |
7 | 144644410104143 |
oct | 20403274415051 |
9 | 4012787605045 |
10 | 1134323440169 |
11 | 3a8078012677 |
12 | 163a0a760035 |
13 | 82c73aa8a9a |
14 | 3cc89bbbc93 |
15 | 1e78de3e1ce |
hex | 1081af21a29 |
1134323440169 has 2 divisors, whose sum is σ = 1134323440170. Its totient is φ = 1134323440168.
The previous prime is 1134323440153. The next prime is 1134323440219. The reversal of 1134323440169 is 9610443234311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1069559298025 + 64764142144 = 1034195^2 + 254488^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134323440169 - 24 = 1134323440153 is a prime.
It is a super-2 number, since 2×11343234401692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1134323440109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567161720084 + 567161720085.
It is an arithmetic number, because the mean of its divisors is an integer number (567161720085).
Almost surely, 21134323440169 is an apocalyptic number.
It is an amenable number.
1134323440169 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134323440169 is an equidigital number, since it uses as much as digits as its factorization.
1134323440169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 41.
The spelling of 1134323440169 in words is "one trillion, one hundred thirty-four billion, three hundred twenty-three million, four hundred forty thousand, one hundred sixty-nine".
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