Base | Representation |
---|---|
bin | 1010010100010000110111… |
… | …1011011110110011010011 |
3 | 1111011101220001122102120122 |
4 | 2211010031323132303103 |
5 | 2441321430013401303 |
6 | 40043002533500455 |
7 | 2250344055620645 |
oct | 245041573366323 |
9 | 44141801572518 |
10 | 11343242325203 |
11 | 3683707636158 |
12 | 1332490aa172b |
13 | 643880c72a29 |
14 | 2b303172a895 |
15 | 14a0e530de38 |
hex | a510dedecd3 |
11343242325203 has 2 divisors, whose sum is σ = 11343242325204. Its totient is φ = 11343242325202.
The previous prime is 11343242325199. The next prime is 11343242325269. The reversal of 11343242325203 is 30252324234311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11343242325203 - 22 = 11343242325199 is a prime.
It is not a weakly prime, because it can be changed into another prime (11343242325293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671621162601 + 5671621162602.
It is an arithmetic number, because the mean of its divisors is an integer number (5671621162602).
Almost surely, 211343242325203 is an apocalyptic number.
11343242325203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343242325203 is an equidigital number, since it uses as much as digits as its factorization.
11343242325203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 11343242325203 its reverse (30252324234311), we get a palindrome (41595566559514).
The spelling of 11343242325203 in words is "eleven trillion, three hundred forty-three billion, two hundred forty-two million, three hundred twenty-five thousand, two hundred three".
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