Base | Representation |
---|---|
bin | 10101001000001110… |
… | …10110000010111011 |
3 | 1002021112110112022001 |
4 | 22210013112002323 |
5 | 141212342321243 |
6 | 5113330441431 |
7 | 551045441323 |
oct | 124407260273 |
9 | 32245415261 |
10 | 11343323323 |
11 | 48a1012782 |
12 | 2246a33277 |
13 | 10ba0b3847 |
14 | 798720283 |
15 | 465ca9a4d |
hex | 2a41d60bb |
11343323323 has 4 divisors (see below), whose sum is σ = 11940340360. Its totient is φ = 10746306288.
The previous prime is 11343323317. The next prime is 11343323371. The reversal of 11343323323 is 32332334311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32332334311 = 49109 ⋅658379.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11343323323 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11343323291 and 11343323300.
It is not an unprimeable number, because it can be changed into a prime (11343323923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298508490 + ... + 298508527.
It is an arithmetic number, because the mean of its divisors is an integer number (2985085090).
Almost surely, 211343323323 is an apocalyptic number.
11343323323 is a deficient number, since it is larger than the sum of its proper divisors (597017037).
11343323323 is an equidigital number, since it uses as much as digits as its factorization.
11343323323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 597017036.
The product of its digits is 11664, while the sum is 28.
Adding to 11343323323 its reverse (32332334311), we get a palindrome (43675657634).
The spelling of 11343323323 in words is "eleven billion, three hundred forty-three million, three hundred twenty-three thousand, three hundred twenty-three".
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