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1134332432003 = 4127666644683
BaseRepresentation
bin10000100000011011011…
…110110100111010000011
311000102220120121000112102
4100200123132310322003
5122041103100311003
62225034412421015
7144644546404331
oct20403336647203
94012816530472
101134332432003
113a80820a4341
12163a1177776b
1382c759067b4
143cc8b07cb51
151e78eb18588
hex1081b7b4e83

1134332432003 has 4 divisors (see below), whose sum is σ = 1161999076728. Its totient is φ = 1106665787280.

The previous prime is 1134332431987. The next prime is 1134332432071. The reversal of 1134332432003 is 3002342334311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134332432003 - 24 = 1134332431987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1134332432083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13833322301 + ... + 13833322382.

It is an arithmetic number, because the mean of its divisors is an integer number (290499769182).

Almost surely, 21134332432003 is an apocalyptic number.

1134332432003 is a deficient number, since it is larger than the sum of its proper divisors (27666644725).

1134332432003 is an equidigital number, since it uses as much as digits as its factorization.

1134332432003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27666644724.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 1134332432003 its reverse (3002342334311), we get a palindrome (4136674766314).

The spelling of 1134332432003 in words is "one trillion, one hundred thirty-four billion, three hundred thirty-two million, four hundred thirty-two thousand, three".

Divisors: 1 41 27666644683 1134332432003