Base | Representation |
---|---|
bin | 110100110100100110… |
… | …0110011100111100011 |
3 | 101211210102022001220011 |
4 | 1221221030303213203 |
5 | 3324303113131111 |
6 | 124035542425351 |
7 | 11124001031113 |
oct | 1515114634743 |
9 | 354712261804 |
10 | 113434114531 |
11 | 4411a6671a1 |
12 | 19b98a32257 |
13 | a909b0873a |
14 | 56c1311043 |
15 | 2e3d83d021 |
hex | 1a693339e3 |
113434114531 has 2 divisors, whose sum is σ = 113434114532. Its totient is φ = 113434114530.
The previous prime is 113434114511. The next prime is 113434114537. The reversal of 113434114531 is 135411434311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113434114531 - 27 = 113434114403 is a prime.
It is a super-2 number, since 2×1134341145312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113434114493 and 113434114502.
It is not a weakly prime, because it can be changed into another prime (113434114537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56717057265 + 56717057266.
It is an arithmetic number, because the mean of its divisors is an integer number (56717057266).
Almost surely, 2113434114531 is an apocalyptic number.
113434114531 is a deficient number, since it is larger than the sum of its proper divisors (1).
113434114531 is an equidigital number, since it uses as much as digits as its factorization.
113434114531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640, while the sum is 31.
Adding to 113434114531 its reverse (135411434311), we get a palindrome (248845548842).
The spelling of 113434114531 in words is "one hundred thirteen billion, four hundred thirty-four million, one hundred fourteen thousand, five hundred thirty-one".
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