Base | Representation |
---|---|
bin | 100001110011100… |
… | …1010110011101001 |
3 | 2221001110111210201 |
4 | 1003213022303221 |
5 | 4310342410403 |
6 | 304320512201 |
7 | 40052512435 |
oct | 10347126351 |
9 | 2831414721 |
10 | 1134341353 |
11 | 5323404a2 |
12 | 277a7b661 |
13 | 151015a02 |
14 | aa91b9c5 |
15 | 698bb21d |
hex | 439cace9 |
1134341353 has 2 divisors, whose sum is σ = 1134341354. Its totient is φ = 1134341352.
The previous prime is 1134341339. The next prime is 1134341357. The reversal of 1134341353 is 3531434311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 690480729 + 443860624 = 26277^2 + 21068^2 .
It is an emirp because it is prime and its reverse (3531434311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134341353 - 217 = 1134210281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134341357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567170676 + 567170677.
It is an arithmetic number, because the mean of its divisors is an integer number (567170677).
Almost surely, 21134341353 is an apocalyptic number.
It is an amenable number.
1134341353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134341353 is an equidigital number, since it uses as much as digits as its factorization.
1134341353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 28.
The square root of 1134341353 is about 33679.9844566472. The cubic root of 1134341353 is about 1042.9126171948.
Adding to 1134341353 its reverse (3531434311), we get a palindrome (4665775664).
The spelling of 1134341353 in words is "one billion, one hundred thirty-four million, three hundred forty-one thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •