1134343320034 has 8 divisors (see below), whose sum is σ = 1701528333228. Its totient is φ = 567167208960.

The previous prime is 1134343320001. The next prime is 1134343320049. The reversal of 1134343320034 is 4300233434311.

It can be written as a sum of positive squares in 2 ways, for example, as 900701596809 + 233641723225 = 949053^2 + 483365^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1134343320034² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1134343319978 and 1134343320005.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1897287 + ... + 2422474.

Almost surely, 2^{1134343320034} is an apocalyptic number.

1134343320034 is a deficient number, since it is larger than the sum of its proper divisors (567185013194).

1134343320034 is a wasteful number, since it uses less digits than its factorization.

1134343320034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4451060.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1134343320034 its reverse (4300233434311), we get a palindrome (5434576754345).

The spelling of 1134343320034 in words is "one trillion, one hundred thirty-four billion, three hundred forty-three million, three hundred twenty thousand, thirty-four".