Base | Representation |
---|---|
bin | 110100110100100110… |
… | …1101011101101011001 |
3 | 101211210102201202001102 |
4 | 1221221031223231121 |
5 | 3324303143004111 |
6 | 124035551401145 |
7 | 11124003005666 |
oct | 1515115535531 |
9 | 354712652042 |
10 | 113434344281 |
11 | 4411a803875 |
12 | 19b98b231b5 |
13 | a909b8919b |
14 | 56c1370a6d |
15 | 2e3d88613b |
hex | 1a6936bb59 |
113434344281 has 2 divisors, whose sum is σ = 113434344282. Its totient is φ = 113434344280.
The previous prime is 113434344269. The next prime is 113434344311. The reversal of 113434344281 is 182443434311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111366368656 + 2067975625 = 333716^2 + 45475^2 .
It is a cyclic number.
It is not a de Polignac number, because 113434344281 - 226 = 113367235417 is a prime.
It is a super-2 number, since 2×1134343442812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113434344181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56717172140 + 56717172141.
It is an arithmetic number, because the mean of its divisors is an integer number (56717172141).
Almost surely, 2113434344281 is an apocalyptic number.
It is an amenable number.
113434344281 is a deficient number, since it is larger than the sum of its proper divisors (1).
113434344281 is an equidigital number, since it uses as much as digits as its factorization.
113434344281 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 110592, while the sum is 38.
Adding to 113434344281 its reverse (182443434311), we get a palindrome (295877778592).
The spelling of 113434344281 in words is "one hundred thirteen billion, four hundred thirty-four million, three hundred forty-four thousand, two hundred eighty-one".
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