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113434740130 = 2553239213067
BaseRepresentation
bin110100110100100111…
…1001100010110100010
3101211210110110212001111
41221221033030112202
53324303243141010
6124040004053534
711124006245035
oct1515117142642
9354713425044
10113434740130
114411aa54218
1219b990942aa
13a909c9740a
1456c143501c
152e3d91358a
hex1a693cc5a2

113434740130 has 16 divisors (see below), whose sum is σ = 204187325760. Its totient is φ = 45372830832.

The previous prime is 113434740103. The next prime is 113434740131. The reversal of 113434740130 is 31047434311.

It is a junction number, because it is equal to n+sod(n) for n = 113434740092 and 113434740101.

It is not an unprimeable number, because it can be changed into a prime (113434740131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 425857 + ... + 638923.

It is an arithmetic number, because the mean of its divisors is an integer number (12761707860).

Almost surely, 2113434740130 is an apocalyptic number.

113434740130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113434740130 is a deficient number, since it is larger than the sum of its proper divisors (90752585630).

113434740130 is a wasteful number, since it uses less digits than its factorization.

113434740130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 266313.

The product of its (nonzero) digits is 12096, while the sum is 31.

The spelling of 113434740130 in words is "one hundred thirteen billion, four hundred thirty-four million, seven hundred forty thousand, one hundred thirty".

Divisors: 1 2 5 10 53239 106478 213067 266195 426134 532390 1065335 2130670 11343474013 22686948026 56717370065 113434740130