Base | Representation |
---|---|
bin | 10101001000010010… |
… | …01000110110011001 |
3 | 1002021120100102100021 |
4 | 22210021020312121 |
5 | 141213002343221 |
6 | 5113344510441 |
7 | 551052440302 |
oct | 124411106631 |
9 | 32246312307 |
10 | 11343793561 |
11 | 48a1304001 |
12 | 224701b421 |
13 | 10ba2198a9 |
14 | 7988037a9 |
15 | 465d4e041 |
hex | 2a4248d99 |
11343793561 has 2 divisors, whose sum is σ = 11343793562. Its totient is φ = 11343793560.
The previous prime is 11343793519. The next prime is 11343793583. The reversal of 11343793561 is 16539734311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8587543561 + 2756250000 = 92669^2 + 52500^2 .
It is a cyclic number.
It is not a de Polignac number, because 11343793561 - 221 = 11341696409 is a prime.
It is not a weakly prime, because it can be changed into another prime (11343793501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671896780 + 5671896781.
It is an arithmetic number, because the mean of its divisors is an integer number (5671896781).
Almost surely, 211343793561 is an apocalyptic number.
It is an amenable number.
11343793561 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343793561 is an equidigital number, since it uses as much as digits as its factorization.
11343793561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 204120, while the sum is 43.
The spelling of 11343793561 in words is "eleven billion, three hundred forty-three million, seven hundred ninety-three thousand, five hundred sixty-one".
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