113442131104243 has 4 divisors (see below), whose sum is σ = 114121425302640. Its totient is φ = 112762836905848.

The previous prime is 113442131104223. The next prime is 113442131104271. The reversal of 113442131104243 is 342401131244311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113442131104243 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113442131104199 and 113442131104208.

It is not an unprimeable number, because it can be changed into a prime (113442131104223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 339647098948 + ... + 339647099281.

It is an arithmetic number, because the mean of its divisors is an integer number (28530356325660).

Almost surely, 2^{113442131104243} is an apocalyptic number.

113442131104243 is a deficient number, since it is larger than the sum of its proper divisors (679294198397).

113442131104243 is an equidigital number, since it uses as much as digits as its factorization.

113442131104243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 679294198396.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 113442131104243 its reverse (342401131244311), we get a palindrome (455843262348554).

The spelling of 113442131104243 in words is "one hundred thirteen trillion, four hundred forty-two billion, one hundred thirty-one million, one hundred four thousand, two hundred forty-three".