Base | Representation |
---|---|
bin | 110100110100111000… |
… | …1111011111100000111 |
3 | 101211211002121120121220 |
4 | 1221221301323330013 |
5 | 3324313111113233 |
6 | 124040531211423 |
7 | 11124146540316 |
oct | 1515161737407 |
9 | 354732546556 |
10 | 113443847943 |
11 | 44125105038 |
12 | 19ba0146b73 |
13 | a90bb35b5a |
14 | 56c272627d |
15 | 2e3e611eb3 |
hex | 1a69c7bf07 |
113443847943 has 16 divisors (see below), whose sum is σ = 152353557600. Its totient is φ = 75082218624.
The previous prime is 113443847939. The next prime is 113443847947. The reversal of 113443847943 is 349748344311.
It is an interprime number because it is at equal distance from previous prime (113443847939) and next prime (113443847947).
It is not a de Polignac number, because 113443847943 - 22 = 113443847939 is a prime.
It is a super-2 number, since 2×1134438479432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113443847947) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 798405 + ... + 929697.
It is an arithmetic number, because the mean of its divisors is an integer number (9522097350).
Almost surely, 2113443847943 is an apocalyptic number.
113443847943 is a deficient number, since it is larger than the sum of its proper divisors (38909709657).
113443847943 is a wasteful number, since it uses less digits than its factorization.
113443847943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133378.
The product of its digits is 3483648, while the sum is 51.
The spelling of 113443847943 in words is "one hundred thirteen billion, four hundred forty-three million, eight hundred forty-seven thousand, nine hundred forty-three".
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