11344414424133 has 32 divisors (see below), whose sum is σ = 17928689593600. Its totient is φ = 6376251631680.

The previous prime is 11344414424111. The next prime is 11344414424159. The reversal of 11344414424133 is 33142441444311.

It is not a de Polignac number, because 11344414424133 - 2¹² = 11344414420037 is a prime.

It is a super-3 number, since 3×11344414424133³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11344414424091 and 11344414424100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11344414404133) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90303610 + ... + 90429147.

It is an arithmetic number, because the mean of its divisors is an integer number (560271549800).

Almost surely, 2^{11344414424133} is an apocalyptic number.

It is an amenable number.

11344414424133 is a deficient number, since it is larger than the sum of its proper divisors (6584275169467).

11344414424133 is an equidigital number, since it uses as much as digits as its factorization.

11344414424133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180732842 (or 180732828 counting only the distinct ones).

The product of its digits is 221184, while the sum is 39.

Adding to 11344414424133 its reverse (33142441444311), we get a palindrome (44486855868444).

The spelling of 11344414424133 in words is "eleven trillion, three hundred forty-four billion, four hundred fourteen million, four hundred twenty-four thousand, one hundred thirty-three".