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11344445017 is a prime number
BaseRepresentation
bin10101001000010111…
…00111111001011001
31002021121120111222021
422210023213321121
5141213134220032
65113410454441
7551061122503
oct124413477131
932247514867
1011344445017
1148a17094a4
122247294421
1310ba3b7279
14798932d73
15465e2c097
hex2a42e7e59

11344445017 has 2 divisors, whose sum is σ = 11344445018. Its totient is φ = 11344445016.

The previous prime is 11344445003. The next prime is 11344445039. The reversal of 11344445017 is 71054444311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8990642761 + 2353802256 = 94819^2 + 48516^2 .

It is an emirp because it is prime and its reverse (71054444311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11344445017 is a prime.

It is a super-2 number, since 2×113444450172 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11344445087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672222508 + 5672222509.

It is an arithmetic number, because the mean of its divisors is an integer number (5672222509).

Almost surely, 211344445017 is an apocalyptic number.

It is an amenable number.

11344445017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11344445017 is an equidigital number, since it uses as much as digits as its factorization.

11344445017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 34.

Adding to 11344445017 its reverse (71054444311), we get a palindrome (82398889328).

The spelling of 11344445017 in words is "eleven billion, three hundred forty-four million, four hundred forty-five thousand, seventeen".