1134453151131 has 4 divisors (see below), whose sum is σ = 1512604201512. Its totient is φ = 756302100752.

The previous prime is 1134453151123. The next prime is 1134453151141. The reversal of 1134453151131 is 1311513544311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134453151131 - 2³ = 1134453151123 is a prime.

It is a super-2 number, since 2×1134453151131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1134453151092 and 1134453151101.

It is not an unprimeable number, because it can be changed into a prime (1134453151141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189075525186 + ... + 189075525191.

It is an arithmetic number, because the mean of its divisors is an integer number (378151050378).

Almost surely, 2^{1134453151131} is an apocalyptic number.

1134453151131 is a deficient number, since it is larger than the sum of its proper divisors (378151050381).

1134453151131 is an equidigital number, since it uses as much as digits as its factorization.

1134453151131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 378151050380.

The product of its digits is 10800, while the sum is 33.

Adding to 1134453151131 its reverse (1311513544311), we get a palindrome (2445966695442).

The spelling of 1134453151131 in words is "one trillion, one hundred thirty-four billion, four hundred fifty-three million, one hundred fifty-one thousand, one hundred thirty-one".