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1134531325043 is a prime number
BaseRepresentation
bin10000100000100111010…
…101100010110001110011
311000110102102211211111022
4100200213111202301303
5122042010004400133
62225110235410055
7144652513101404
oct20404725426163
94013372754438
101134531325043
113a81743a0656
12163a682b392b
1382ca7b93c9c
143cca96539ab
151e7a2304998
hex10827562c73

1134531325043 has 2 divisors, whose sum is σ = 1134531325044. Its totient is φ = 1134531325042.

The previous prime is 1134531325003. The next prime is 1134531325063. The reversal of 1134531325043 is 3405231354311.

It is a strong prime.

It is an emirp because it is prime and its reverse (3405231354311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134531325043 - 212 = 1134531320947 is a prime.

It is a super-2 number, since 2×11345313250432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1134531324994 and 1134531325012.

It is not a weakly prime, because it can be changed into another prime (1134531325003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567265662521 + 567265662522.

It is an arithmetic number, because the mean of its divisors is an integer number (567265662522).

Almost surely, 21134531325043 is an apocalyptic number.

1134531325043 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134531325043 is an equidigital number, since it uses as much as digits as its factorization.

1134531325043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 1134531325043 its reverse (3405231354311), we get a palindrome (4539762679354).

The spelling of 1134531325043 in words is "one trillion, one hundred thirty-four billion, five hundred thirty-one million, three hundred twenty-five thousand, forty-three".