Base | Representation |
---|---|
bin | 110100110101011010… |
… | …0101101000000100001 |
3 | 101211212022112210112021 |
4 | 1221222310231000201 |
5 | 3324332101203213 |
6 | 124042354301441 |
7 | 11124451365064 |
oct | 1515264550041 |
9 | 354768483467 |
10 | 113461350433 |
11 | 44133a79a02 |
12 | 19ba5b87881 |
13 | a912653562 |
14 | 56c4ba08db |
15 | 2e40e1cd8d |
hex | 1a6ad2d021 |
113461350433 has 2 divisors, whose sum is σ = 113461350434. Its totient is φ = 113461350432.
The previous prime is 113461350319. The next prime is 113461350487. The reversal of 113461350433 is 334053164311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113011613584 + 449736849 = 336172^2 + 21207^2 .
It is an emirp because it is prime and its reverse (334053164311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113461350433 - 233 = 104871415841 is a prime.
It is not a weakly prime, because it can be changed into another prime (113461351433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56730675216 + 56730675217.
It is an arithmetic number, because the mean of its divisors is an integer number (56730675217).
Almost surely, 2113461350433 is an apocalyptic number.
It is an amenable number.
113461350433 is a deficient number, since it is larger than the sum of its proper divisors (1).
113461350433 is an equidigital number, since it uses as much as digits as its factorization.
113461350433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
The spelling of 113461350433 in words is "one hundred thirteen billion, four hundred sixty-one million, three hundred fifty thousand, four hundred thirty-three".
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