Base | Representation |
---|---|
bin | 11001110011000101001100… |
… | …011101110101010010011001 |
3 | 112212201210210102012022012002 |
4 | 121303011030131311102121 |
5 | 104332423004042303124 |
6 | 1041151244014130345 |
7 | 32620214050564001 |
oct | 3163051435652231 |
9 | 485653712168162 |
10 | 113461433947289 |
11 | 331747a659112a |
12 | 108857047b09b5 |
13 | 4b404a0ca2b9c |
14 | 20037c40bb001 |
15 | d1b5d3e010ae |
hex | 67314c775499 |
113461433947289 has 2 divisors, whose sum is σ = 113461433947290. Its totient is φ = 113461433947288.
The previous prime is 113461433947241. The next prime is 113461433947321. The reversal of 113461433947289 is 982749334164311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110399843879689 + 3061590067600 = 10507133^2 + 1749740^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113461433947289 is a prime.
It is a super-3 number, since 3×1134614339472893 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (113461433947789) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56730716973644 + 56730716973645.
It is an arithmetic number, because the mean of its divisors is an integer number (56730716973645).
Almost surely, 2113461433947289 is an apocalyptic number.
It is an amenable number.
113461433947289 is a deficient number, since it is larger than the sum of its proper divisors (1).
113461433947289 is an equidigital number, since it uses as much as digits as its factorization.
113461433947289 is an evil number, because the sum of its binary digits is even.
The product of its digits is 94058496, while the sum is 65.
The spelling of 113461433947289 in words is "one hundred thirteen trillion, four hundred sixty-one billion, four hundred thirty-three million, nine hundred forty-seven thousand, two hundred eighty-nine".
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