Base | Representation |
---|---|
bin | 10000100001000101110… |
… | …110101010100110111011 |
3 | 11000111202010021002111111 |
4 | 100201011312222212323 |
5 | 122044032042334342 |
6 | 2225233125341151 |
7 | 145001301032632 |
oct | 20410566524673 |
9 | 4014663232444 |
10 | 1135043324347 |
11 | 3a8407403279 |
12 | 163b8b8677b7 |
13 | 83059c8a95a |
14 | 3cd17650519 |
15 | 1e7d223d217 |
hex | 10845daa9bb |
1135043324347 has 2 divisors, whose sum is σ = 1135043324348. Its totient is φ = 1135043324346.
The previous prime is 1135043324299. The next prime is 1135043324351. The reversal of 1135043324347 is 7434233405311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1135043324347 - 223 = 1135034935739 is a prime.
It is not a weakly prime, because it can be changed into another prime (1135043324047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567521662173 + 567521662174.
It is an arithmetic number, because the mean of its divisors is an integer number (567521662174).
Almost surely, 21135043324347 is an apocalyptic number.
1135043324347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135043324347 is an equidigital number, since it uses as much as digits as its factorization.
1135043324347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 40.
Adding to 1135043324347 its reverse (7434233405311), we get a palindrome (8569276729658).
The spelling of 1135043324347 in words is "one trillion, one hundred thirty-five billion, forty-three million, three hundred twenty-four thousand, three hundred forty-seven".
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