Base | Representation |
---|---|
bin | 1010010100101110100001… |
… | …1000110110010101000011 |
3 | 1111012011102210222100111110 |
4 | 2211023220120312111003 |
5 | 2441434230310033011 |
6 | 40050400450214403 |
7 | 2251045243424313 |
oct | 245135030662503 |
9 | 44164383870443 |
10 | 11351202424131 |
11 | 3687021930309 |
12 | 1333b32884403 |
13 | 64454c15533b |
14 | 2b35889a9443 |
15 | 14a40e076ba6 |
hex | a52e8636543 |
11351202424131 has 16 divisors (see below), whose sum is σ = 15246082849184. Its totient is φ = 7511988466944.
The previous prime is 11351202424103. The next prime is 11351202424153. The reversal of 11351202424131 is 13142420215311.
It is not a de Polignac number, because 11351202424131 - 210 = 11351202423107 is a prime.
It is a super-2 number, since 2×113512024241312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11351202424171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11178616 + ... + 12151701.
It is an arithmetic number, because the mean of its divisors is an integer number (952880178074).
Almost surely, 211351202424131 is an apocalyptic number.
11351202424131 is a deficient number, since it is larger than the sum of its proper divisors (3894880425053).
11351202424131 is a wasteful number, since it uses less digits than its factorization.
11351202424131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23331510.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 11351202424131 its reverse (13142420215311), we get a palindrome (24493622639442).
The spelling of 11351202424131 in words is "eleven trillion, three hundred fifty-one billion, two hundred two million, four hundred twenty-four thousand, one hundred thirty-one".
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