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113515220441033 is a prime number
BaseRepresentation
bin11001110011110111010010…
…011001000001011111001001
3112212220221121212222021201222
4121303313102121001133021
5104334313132413103113
61041232101121251425
732624126661334055
oct3163672231013711
9485827555867658
10113515220441033
113319559766aa54
1210894015793b75
134b4559335b548
142006247664c65
15d1cbd0de4e08
hex673dd26417c9

113515220441033 has 2 divisors, whose sum is σ = 113515220441034. Its totient is φ = 113515220441032.

The previous prime is 113515220440949. The next prime is 113515220441053. The reversal of 113515220441033 is 330144022515311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90221730214144 + 23293490226889 = 9498512^2 + 4826333^2 .

It is a cyclic number.

It is not a de Polignac number, because 113515220441033 - 220 = 113515219392457 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113515220440984 and 113515220441002.

It is not a weakly prime, because it can be changed into another prime (113515220441053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56757610220516 + 56757610220517.

It is an arithmetic number, because the mean of its divisors is an integer number (56757610220517).

Almost surely, 2113515220441033 is an apocalyptic number.

It is an amenable number.

113515220441033 is a deficient number, since it is larger than the sum of its proper divisors (1).

113515220441033 is an equidigital number, since it uses as much as digits as its factorization.

113515220441033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 113515220441033 its reverse (330144022515311), we get a palindrome (443659242956344).

The spelling of 113515220441033 in words is "one hundred thirteen trillion, five hundred fifteen billion, two hundred twenty million, four hundred forty-one thousand, thirty-three".