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113523302540107 is a prime number
BaseRepresentation
bin11001110011111110110100…
…000111110010001101001011
3112212221201111010212110101201
4121303332310013302031023
5104334431210422240412
61041235515112525031
732624534160132115
oct3163766407621513
9485851433773351
10113523302540107
1133198a64812679
12108956b03b0777
134b462808b82a5
1420067b2bc03b5
15d1d00570ae57
hex673fb41f234b

113523302540107 has 2 divisors, whose sum is σ = 113523302540108. Its totient is φ = 113523302540106.

The previous prime is 113523302539991. The next prime is 113523302540159. The reversal of 113523302540107 is 701045203325311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113523302540107 - 219 = 113523302015819 is a prime.

It is a super-2 number, since 2×1135233025401072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113523302540707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56761651270053 + 56761651270054.

It is an arithmetic number, because the mean of its divisors is an integer number (56761651270054).

Almost surely, 2113523302540107 is an apocalyptic number.

113523302540107 is a deficient number, since it is larger than the sum of its proper divisors (1).

113523302540107 is an equidigital number, since it uses as much as digits as its factorization.

113523302540107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 37.

Adding to 113523302540107 its reverse (701045203325311), we get a palindrome (814568505865418).

The spelling of 113523302540107 in words is "one hundred thirteen trillion, five hundred twenty-three billion, three hundred two million, five hundred forty thousand, one hundred seven".