Base | Representation |
---|---|
bin | 110100110111100000… |
… | …0010110001000001011 |
3 | 101212001012120100011011 |
4 | 1221233000112020023 |
5 | 3330003031330212 |
6 | 124053342144351 |
7 | 11126262631534 |
oct | 1515700261013 |
9 | 355035510134 |
10 | 113531511307 |
11 | 4416a63a8a5 |
12 | 1a0055820b7 |
13 | a92404a376 |
14 | 56d022568b |
15 | 2e4717b4a7 |
hex | 1a6f01620b |
113531511307 has 2 divisors, whose sum is σ = 113531511308. Its totient is φ = 113531511306.
The previous prime is 113531511299. The next prime is 113531511361. The reversal of 113531511307 is 703115135311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113531511307 - 23 = 113531511299 is a prime.
It is not a weakly prime, because it can be changed into another prime (113531511367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56765755653 + 56765755654.
It is an arithmetic number, because the mean of its divisors is an integer number (56765755654).
Almost surely, 2113531511307 is an apocalyptic number.
113531511307 is a deficient number, since it is larger than the sum of its proper divisors (1).
113531511307 is an equidigital number, since it uses as much as digits as its factorization.
113531511307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4725, while the sum is 31.
Adding to 113531511307 its reverse (703115135311), we get a palindrome (816646646618).
The spelling of 113531511307 in words is "one hundred thirteen billion, five hundred thirty-one million, five hundred eleven thousand, three hundred seven".
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