Base | Representation |
---|---|
bin | 11001110100001001010000… |
… | …111011001101001000101010 |
3 | 112212222210110010112001011022 |
4 | 121310021100323031020222 |
5 | 104340122200414400132 |
6 | 1041245012342332442 |
7 | 32625412216150310 |
oct | 3164112073151052 |
9 | 485883403461138 |
10 | 113534523200042 |
11 | 331a27a256454a |
12 | 1089790212a122 |
13 | 4b4734b451839 |
14 | 20071590d00b0 |
15 | d1d460835e12 |
hex | 674250ecd22a |
113534523200042 has 8 divisors (see below), whose sum is σ = 194630611200096. Its totient is φ = 48657652800012.
The previous prime is 113534523200027. The next prime is 113534523200047. The reversal of 113534523200042 is 240002325435311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 113534523199975 and 113534523200011.
It is not an unprimeable number, because it can be changed into a prime (113534523200047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4054804399988 + ... + 4054804400015.
It is an arithmetic number, because the mean of its divisors is an integer number (24328826400012).
Almost surely, 2113534523200042 is an apocalyptic number.
113534523200042 is a deficient number, since it is larger than the sum of its proper divisors (81096088000054).
113534523200042 is an equidigital number, since it uses as much as digits as its factorization.
113534523200042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8109608800012.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 113534523200042 its reverse (240002325435311), we get a palindrome (353536848635353).
The spelling of 113534523200042 in words is "one hundred thirteen trillion, five hundred thirty-four billion, five hundred twenty-three million, two hundred thousand, forty-two".
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