113540040431113 has 8 divisors (see below), whose sum is σ = 113780060226560. Its totient is φ = 113300048825280.

The previous prime is 113540040431099. The next prime is 113540040431119. The reversal of 113540040431113 is 311134040045311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113540040431113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113540040431119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1026328 + ... + 15104086.

It is an arithmetic number, because the mean of its divisors is an integer number (14222507528320).

Almost surely, 2^{113540040431113} is an apocalyptic number.

It is an amenable number.

113540040431113 is a deficient number, since it is larger than the sum of its proper divisors (240019795447).

113540040431113 is a wasteful number, since it uses less digits than its factorization.

113540040431113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14094807.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 113540040431113 its reverse (311134040045311), we get a palindrome (424674080476424).

The spelling of 113540040431113 in words is "one hundred thirteen trillion, five hundred forty billion, forty million, four hundred thirty-one thousand, one hundred thirteen".