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113540042540347 is a prime number
BaseRepresentation
bin11001110100001110011001…
…111001110100010100111011
3112220000022200210010120200121
4121310032121321310110323
5104340220001342242342
61041251324145114111
732625666045602413
oct3164163171642473
9486008623116617
10113540042540347
11331a5075038615
12108989a2628937
134b47a1aa77587
14200752013d643
15d1d685176067
hex674399e7453b

113540042540347 has 2 divisors, whose sum is σ = 113540042540348. Its totient is φ = 113540042540346.

The previous prime is 113540042540279. The next prime is 113540042540377. The reversal of 113540042540347 is 743045240045311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113540042540347 is a prime.

It is a super-2 number, since 2×1135400425403472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113540042540377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56770021270173 + 56770021270174.

It is an arithmetic number, because the mean of its divisors is an integer number (56770021270174).

Almost surely, 2113540042540347 is an apocalyptic number.

113540042540347 is a deficient number, since it is larger than the sum of its proper divisors (1).

113540042540347 is an equidigital number, since it uses as much as digits as its factorization.

113540042540347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 806400, while the sum is 43.

Adding to 113540042540347 its reverse (743045240045311), we get a palindrome (856585282585658).

The spelling of 113540042540347 in words is "one hundred thirteen trillion, five hundred forty billion, forty-two million, five hundred forty thousand, three hundred forty-seven".