Base | Representation |
---|---|
bin | 11001110100001110011001… |
… | …111001110101000011100001 |
3 | 112220000022200210010201210001 |
4 | 121310032121321311003201 |
5 | 104340220001342341304 |
6 | 1041251324145140001 |
7 | 32625666045614203 |
oct | 3164163171650341 |
9 | 486008623121701 |
10 | 113540042543329 |
11 | 331a507503a886 |
12 | 108989a262a601 |
13 | 4b47a1aa78a3c |
14 | 2007520140773 |
15 | d1d685176da4 |
hex | 674399e750e1 |
113540042543329 has 2 divisors, whose sum is σ = 113540042543330. Its totient is φ = 113540042543328.
The previous prime is 113540042543321. The next prime is 113540042543339. The reversal of 113540042543329 is 923345240045311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 85821418080225 + 27718624463104 = 9263985^2 + 5264848^2 .
It is a cyclic number.
It is not a de Polignac number, because 113540042543329 - 23 = 113540042543321 is a prime.
It is not a weakly prime, because it can be changed into another prime (113540042543321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56770021271664 + 56770021271665.
It is an arithmetic number, because the mean of its divisors is an integer number (56770021271665).
Almost surely, 2113540042543329 is an apocalyptic number.
It is an amenable number.
113540042543329 is a deficient number, since it is larger than the sum of its proper divisors (1).
113540042543329 is an equidigital number, since it uses as much as digits as its factorization.
113540042543329 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 46.
The spelling of 113540042543329 in words is "one hundred thirteen trillion, five hundred forty billion, forty-two million, five hundred forty-three thousand, three hundred twenty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •