Base | Representation |
---|---|
bin | 11001110100001111110010… |
… | …000111001100111011101011 |
3 | 112220000110111220211110212102 |
4 | 121310033302013030323223 |
5 | 104340231014221202021 |
6 | 1041252131052404015 |
7 | 32626050525560354 |
oct | 3164176207147353 |
9 | 486013456743772 |
10 | 113541522444011 |
11 | 331a57644420a2 |
12 | 1089913617660b |
13 | 4b47bc555160c |
14 | 20076208d0d2b |
15 | d1d72005100b |
hex | 6743f21cceeb |
113541522444011 has 2 divisors, whose sum is σ = 113541522444012. Its totient is φ = 113541522444010.
The previous prime is 113541522444001. The next prime is 113541522444121. The reversal of 113541522444011 is 110444225145311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113541522444011 - 210 = 113541522442987 is a prime.
It is not a weakly prime, because it can be changed into another prime (113541522444001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56770761222005 + 56770761222006.
It is an arithmetic number, because the mean of its divisors is an integer number (56770761222006).
Almost surely, 2113541522444011 is an apocalyptic number.
113541522444011 is a deficient number, since it is larger than the sum of its proper divisors (1).
113541522444011 is an equidigital number, since it uses as much as digits as its factorization.
113541522444011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 76800, while the sum is 38.
Adding to 113541522444011 its reverse (110444225145311), we get a palindrome (223985747589322).
The spelling of 113541522444011 in words is "one hundred thirteen trillion, five hundred forty-one billion, five hundred twenty-two million, four hundred forty-four thousand, eleven".
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