Base | Representation |
---|---|
bin | 11001110100010000001110… |
… | …100101010111001001111011 |
3 | 112220000111202012122112111201 |
4 | 121310100032211113021323 |
5 | 104340233004012043001 |
6 | 1041252250314435031 |
7 | 32626065415644214 |
oct | 3164201645271173 |
9 | 486014665575451 |
10 | 113542000112251 |
11 | 331a598a036337 |
12 | 1089924a132a77 |
13 | 4b47c704b7b49 |
14 | 200766811240b |
15 | d1d74be57501 |
hex | 67440e95727b |
113542000112251 has 2 divisors, whose sum is σ = 113542000112252. Its totient is φ = 113542000112250.
The previous prime is 113542000112201. The next prime is 113542000112263. The reversal of 113542000112251 is 152211000245311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113542000112251 - 29 = 113542000111739 is a prime.
It is not a weakly prime, because it can be changed into another prime (113542000112201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56771000056125 + 56771000056126.
It is an arithmetic number, because the mean of its divisors is an integer number (56771000056126).
Almost surely, 2113542000112251 is an apocalyptic number.
113542000112251 is a deficient number, since it is larger than the sum of its proper divisors (1).
113542000112251 is an equidigital number, since it uses as much as digits as its factorization.
113542000112251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 113542000112251 its reverse (152211000245311), we get a palindrome (265753000357562).
The spelling of 113542000112251 in words is "one hundred thirteen trillion, five hundred forty-two billion, one hundred twelve thousand, two hundred fifty-one".
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