113542123511033 has 8 divisors (see below), whose sum is σ = 129853616218368. Its totient is φ = 97253428140864.

The previous prime is 113542123511023. The next prime is 113542123511099. The reversal of 113542123511033 is 330115321245311.

113542123511033 is digitally balanced in base 8, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113542123511033 - 2¹⁰ = 113542123510009 is a prime.

It is a super-2 number, since 2×113542123511033² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113542123510984 and 113542123511002.

It is not an unprimeable number, because it can be changed into a prime (113542123511023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5699323616 + ... + 5699343537.

It is an arithmetic number, because the mean of its divisors is an integer number (16231702027296).

Almost surely, 2^{113542123511033} is an apocalyptic number.

It is an amenable number.

113542123511033 is a deficient number, since it is larger than the sum of its proper divisors (16311492707335).

113542123511033 is a wasteful number, since it uses less digits than its factorization.

113542123511033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11398668583.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 113542123511033 its reverse (330115321245311), we get a palindrome (443657444756344).

The spelling of 113542123511033 in words is "one hundred thirteen trillion, five hundred forty-two billion, one hundred twenty-three million, five hundred eleven thousand, thirty-three".