Base | Representation |
---|---|
bin | 110100110111110110… |
… | …0100110000111011011 |
3 | 101212002000101200010021 |
4 | 1221233230212013123 |
5 | 3330014014024011 |
6 | 124054434531311 |
7 | 11126463343342 |
oct | 1515754460733 |
9 | 355060350107 |
10 | 113543111131 |
11 | 44176142a2a |
12 | 1a009436b37 |
13 | a92657c178 |
14 | 56d19a4b59 |
15 | 2e481bd471 |
hex | 1a6fb261db |
113543111131 has 2 divisors, whose sum is σ = 113543111132. Its totient is φ = 113543111130.
The previous prime is 113543111117. The next prime is 113543111177. The reversal of 113543111131 is 131111345311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113543111131 - 229 = 113006240219 is a prime.
It is a super-2 number, since 2×1135431111312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113543111096 and 113543111105.
It is not a weakly prime, because it can be changed into another prime (113543111111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56771555565 + 56771555566.
It is an arithmetic number, because the mean of its divisors is an integer number (56771555566).
Almost surely, 2113543111131 is an apocalyptic number.
113543111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
113543111131 is an equidigital number, since it uses as much as digits as its factorization.
113543111131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 540, while the sum is 25.
Adding to 113543111131 its reverse (131111345311), we get a palindrome (244654456442).
The spelling of 113543111131 in words is "one hundred thirteen billion, five hundred forty-three million, one hundred eleven thousand, one hundred thirty-one".
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