Base | Representation |
---|---|
bin | 10101001001101000… |
… | …00101010001111011 |
3 | 1002022100112100211022 |
4 | 22210310011101323 |
5 | 141223343114011 |
6 | 5114430053055 |
7 | 551250225224 |
oct | 124464052173 |
9 | 32270470738 |
10 | 11355051131 |
11 | 48a76a2a86 |
12 | 224a94a18b |
13 | 10bc65b988 |
14 | 79a0d424b |
15 | 466d248db |
hex | 2a4d0547b |
11355051131 has 2 divisors, whose sum is σ = 11355051132. Its totient is φ = 11355051130.
The previous prime is 11355051121. The next prime is 11355051137. The reversal of 11355051131 is 13115055311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11355051131 - 26 = 11355051067 is a prime.
It is a super-2 number, since 2×113550511312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11355051131.
It is not a weakly prime, because it can be changed into another prime (11355051137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677525565 + 5677525566.
It is an arithmetic number, because the mean of its divisors is an integer number (5677525566).
Almost surely, 211355051131 is an apocalyptic number.
11355051131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11355051131 is an equidigital number, since it uses as much as digits as its factorization.
11355051131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1125, while the sum is 26.
The spelling of 11355051131 in words is "eleven billion, three hundred fifty-five million, fifty-one thousand, one hundred thirty-one".
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