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113553011233433 is a prime number
BaseRepresentation
bin11001110100011010011110…
…111001011101001010011001
3112220001120011121000110010202
4121310122132321131022121
5104340423031333432213
61041301311101151545
732626635321636302
oct3164323671351231
9486046147013122
10113553011233433
11331aa61a57a692
121089b40185b5b5
134b49006807475
142007dd06797a9
15d1db93991b58
hex67469ee5d299

113553011233433 has 2 divisors, whose sum is σ = 113553011233434. Its totient is φ = 113553011233432.

The previous prime is 113553011233427. The next prime is 113553011233463. The reversal of 113553011233433 is 334332110355311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86257433350144 + 27295577883289 = 9287488^2 + 5224517^2 .

It is a cyclic number.

It is not a de Polignac number, because 113553011233433 - 220 = 113553010184857 is a prime.

It is a super-2 number, since 2×1135530112334332 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113553011233463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776505616716 + 56776505616717.

It is an arithmetic number, because the mean of its divisors is an integer number (56776505616717).

Almost surely, 2113553011233433 is an apocalyptic number.

It is an amenable number.

113553011233433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113553011233433 is an equidigital number, since it uses as much as digits as its factorization.

113553011233433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 38.

Adding to 113553011233433 its reverse (334332110355311), we get a palindrome (447885121588744).

The spelling of 113553011233433 in words is "one hundred thirteen trillion, five hundred fifty-three billion, eleven million, two hundred thirty-three thousand, four hundred thirty-three".