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113553452431241 is a prime number
BaseRepresentation
bin11001110100011010111001…
…001100011111011110001001
3112220001121022100012121202022
4121310122321030133132021
5104340424432310244431
61041301422541414225
732626652260025264
oct3164327114373611
9486047270177668
10113553452431241
11331aa826624079
121089b50556a375
134b49077041864
1420080330c5cdb
15d1dbbc59207b
hex6746b931f789

113553452431241 has 2 divisors, whose sum is σ = 113553452431242. Its totient is φ = 113553452431240.

The previous prime is 113553452431229. The next prime is 113553452431261. The reversal of 113553452431241 is 142134254355311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75138298015225 + 38415154416016 = 8668235^2 + 6197996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113553452431241 is a prime.

It is a super-2 number, since 2×1135534524312412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113553452431192 and 113553452431201.

It is not a weakly prime, because it can be changed into another prime (113553452431261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776726215620 + 56776726215621.

It is an arithmetic number, because the mean of its divisors is an integer number (56776726215621).

Almost surely, 2113553452431241 is an apocalyptic number.

It is an amenable number.

113553452431241 is a deficient number, since it is larger than the sum of its proper divisors (1).

113553452431241 is an equidigital number, since it uses as much as digits as its factorization.

113553452431241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 864000, while the sum is 44.

The spelling of 113553452431241 in words is "one hundred thirteen trillion, five hundred fifty-three billion, four hundred fifty-two million, four hundred thirty-one thousand, two hundred forty-one".