Base | Representation |
---|---|
bin | 11001110100011010111110… |
… | …000101001110110100100001 |
3 | 112220001121112001110210002222 |
4 | 121310122332011032310201 |
5 | 104340430114302222423 |
6 | 1041301435030520425 |
7 | 32626654303620353 |
oct | 3164327605166441 |
9 | 486047461423088 |
10 | 113553534414113 |
11 | 331aa86892a012 |
12 | 1089b528b06115 |
13 | 4b4908b017631 |
14 | 200803dd470d3 |
15 | d1dbc48883c8 |
hex | 6746be14ed21 |
113553534414113 has 2 divisors, whose sum is σ = 113553534414114. Its totient is φ = 113553534414112.
The previous prime is 113553534414079. The next prime is 113553534414127. The reversal of 113553534414113 is 311414435355311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113547181845904 + 6352568209 = 10655852^2 + 79703^2 .
It is a cyclic number.
It is not a de Polignac number, because 113553534414113 - 28 = 113553534413857 is a prime.
It is not a weakly prime, because it can be changed into another prime (113553534414163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776767207056 + 56776767207057.
It is an arithmetic number, because the mean of its divisors is an integer number (56776767207057).
Almost surely, 2113553534414113 is an apocalyptic number.
It is an amenable number.
113553534414113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113553534414113 is an equidigital number, since it uses as much as digits as its factorization.
113553534414113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648000, while the sum is 44.
Adding to 113553534414113 its reverse (311414435355311), we get a palindrome (424967969769424).
The spelling of 113553534414113 in words is "one hundred thirteen trillion, five hundred fifty-three billion, five hundred thirty-four million, four hundred fourteen thousand, one hundred thirteen".
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