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113555004310273 is a prime number
BaseRepresentation
bin11001110100011100010101…
…101100011100001100000001
3112220001202022111100020120111
4121310130111230130030001
5104340441122100412043
61041302240535511321
732630035602545041
oct3164342554341401
9486052274306514
10113555004310273
1133200452618829
121089b879228541
134b492636c9586
14200813d251721
15d1dc5d93809d
hex674715b1c301

113555004310273 has 2 divisors, whose sum is σ = 113555004310274. Its totient is φ = 113555004310272.

The previous prime is 113555004310217. The next prime is 113555004310291. The reversal of 113555004310273 is 372013400555311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67822340226624 + 45732664083649 = 8235432^2 + 6762593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113555004310273 is a prime.

It is a super-2 number, since 2×1135550043102732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113555004310973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777502155136 + 56777502155137.

It is an arithmetic number, because the mean of its divisors is an integer number (56777502155137).

Almost surely, 2113555004310273 is an apocalyptic number.

It is an amenable number.

113555004310273 is a deficient number, since it is larger than the sum of its proper divisors (1).

113555004310273 is an equidigital number, since it uses as much as digits as its factorization.

113555004310273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 189000, while the sum is 40.

Adding to 113555004310273 its reverse (372013400555311), we get a palindrome (485568404865584).

The spelling of 113555004310273 in words is "one hundred thirteen trillion, five hundred fifty-five billion, four million, three hundred ten thousand, two hundred seventy-three".