Search a number
-
+
113555302241 is a prime number
BaseRepresentation
bin110100111000001101…
…1000110011101100001
3101212002212100001011212
41221300123012131201
53330030124132431
6124055552115505
711130002100053
oct1516033063541
9355085301155
10113555302241
114418200a327
121a011535b95
13a928c5a144
1456d34598d3
152e492ca72b
hex1a706c6761

113555302241 has 2 divisors, whose sum is σ = 113555302242. Its totient is φ = 113555302240.

The previous prime is 113555302229. The next prime is 113555302247. The reversal of 113555302241 is 142203555311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86968369216 + 26586933025 = 294904^2 + 163055^2 .

It is an emirp because it is prime and its reverse (142203555311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113555302241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113555302198 and 113555302207.

It is not a weakly prime, because it can be changed into another prime (113555302247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777651120 + 56777651121.

It is an arithmetic number, because the mean of its divisors is an integer number (56777651121).

Almost surely, 2113555302241 is an apocalyptic number.

It is an amenable number.

113555302241 is a deficient number, since it is larger than the sum of its proper divisors (1).

113555302241 is an equidigital number, since it uses as much as digits as its factorization.

113555302241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 113555302241 its reverse (142203555311), we get a palindrome (255758857552).

The spelling of 113555302241 in words is "one hundred thirteen billion, five hundred fifty-five million, three hundred two thousand, two hundred forty-one".