Base | Representation |
---|---|
bin | 110100111000011001… |
… | …0100000010000110001 |
3 | 101212010021212201210210 |
4 | 1221300302200100301 |
5 | 3330033211442413 |
6 | 124100331414333 |
7 | 11130105201246 |
oct | 1516062402061 |
9 | 355107781723 |
10 | 113561437233 |
11 | 4418551a672 |
12 | 1a0135b43a9 |
13 | a92a2c770a |
14 | 56d41b55cd |
15 | 2e49add3c3 |
hex | 1a70ca0431 |
113561437233 has 8 divisors (see below), whose sum is σ = 151512379200. Its totient is φ = 75659060048.
The previous prime is 113561437229. The next prime is 113561437247. The reversal of 113561437233 is 332734165311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113561437233 - 22 = 113561437229 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 113561437191 and 113561437200.
It is not an unprimeable number, because it can be changed into a prime (113561437133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12135738 + ... + 12145091.
It is an arithmetic number, because the mean of its divisors is an integer number (18939047400).
Almost surely, 2113561437233 is an apocalyptic number.
It is an amenable number.
113561437233 is a deficient number, since it is larger than the sum of its proper divisors (37950941967).
113561437233 is a wasteful number, since it uses less digits than its factorization.
113561437233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24282391.
The product of its digits is 136080, while the sum is 39.
The spelling of 113561437233 in words is "one hundred thirteen billion, five hundred sixty-one million, four hundred thirty-seven thousand, two hundred thirty-three".
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