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11368289433121 is a prime number
BaseRepresentation
bin1010010101101110001011…
…0110100111011000100001
31111020210112122012100022021
42211123202312213120201
52442224224043324441
640102304200141441
72252221544543125
oct245334266473041
944223478170267
1011368289433121
1136932a0018045
121337301167881
1364604319114a
142b432a057585
1514aaae1d93d1
hexa56e2da7621

11368289433121 has 2 divisors, whose sum is σ = 11368289433122. Its totient is φ = 11368289433120.

The previous prime is 11368289433091. The next prime is 11368289433131. The reversal of 11368289433121 is 12133498286311.

11368289433121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7253132330896 + 4115157102225 = 2693164^2 + 2028585^2 .

It is a cyclic number.

It is not a de Polignac number, because 11368289433121 - 211 = 11368289431073 is a prime.

It is not a weakly prime, because it can be changed into another prime (11368289433131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5684144716560 + 5684144716561.

It is an arithmetic number, because the mean of its divisors is an integer number (5684144716561).

Almost surely, 211368289433121 is an apocalyptic number.

It is an amenable number.

11368289433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11368289433121 is an equidigital number, since it uses as much as digits as its factorization.

11368289433121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1492992, while the sum is 52.

The spelling of 11368289433121 in words is "eleven trillion, three hundred sixty-eight billion, two hundred eighty-nine million, four hundred thirty-three thousand, one hundred twenty-one".