Base | Representation |
---|---|
bin | 11001111000100000111011… |
… | …110101101010001001110001 |
3 | 112221001111120010112112011101 |
4 | 121320200323311222021301 |
5 | 104410032201141311332 |
6 | 1042034554255444401 |
7 | 32656202613402553 |
oct | 3170407365521161 |
9 | 487044503475141 |
10 | 113834817135217 |
11 | 332a9090672682 |
12 | 10925b49b26701 |
13 | 4b69767136889 |
14 | 20178c52a74d3 |
15 | d26188c06ae7 |
hex | 67883bd6a271 |
113834817135217 has 4 divisors (see below), whose sum is σ = 114533190246640. Its totient is φ = 113136444023796.
The previous prime is 113834817135191. The next prime is 113834817135227. The reversal of 113834817135217 is 712531718438311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113834817135217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113834817135227) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 349186555467 + ... + 349186555792.
It is an arithmetic number, because the mean of its divisors is an integer number (28633297561660).
Almost surely, 2113834817135217 is an apocalyptic number.
It is an amenable number.
113834817135217 is a deficient number, since it is larger than the sum of its proper divisors (698373111423).
113834817135217 is an equidigital number, since it uses as much as digits as its factorization.
113834817135217 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 698373111422.
The product of its digits is 3386880, while the sum is 55.
The spelling of 113834817135217 in words is "one hundred thirteen trillion, eight hundred thirty-four billion, eight hundred seventeen million, one hundred thirty-five thousand, two hundred seventeen".
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