Base | Representation |
---|---|
bin | 1010010111010101011100… |
… | …1111111001101111101011 |
3 | 1111100110002200010210222121 |
4 | 2211311113033321233223 |
5 | 2443203013034212023 |
6 | 40123131115332111 |
7 | 2254222541633464 |
oct | 245652717715753 |
9 | 44313080123877 |
10 | 11396012022763 |
11 | 36a4026769a55 |
12 | 1340759451037 |
13 | 648840790144 |
14 | 2b57d9c33d6b |
15 | 14b682e04d5d |
hex | a5d573f9beb |
11396012022763 has 2 divisors, whose sum is σ = 11396012022764. Its totient is φ = 11396012022762.
The previous prime is 11396012022701. The next prime is 11396012022821. The reversal of 11396012022763 is 36722021069311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11396012022763 - 221 = 11396009925611 is a prime.
It is a super-3 number, since 3×113960120227633 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11396012025763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5698006011381 + 5698006011382.
It is an arithmetic number, because the mean of its divisors is an integer number (5698006011382).
Almost surely, 211396012022763 is an apocalyptic number.
11396012022763 is a deficient number, since it is larger than the sum of its proper divisors (1).
11396012022763 is an equidigital number, since it uses as much as digits as its factorization.
11396012022763 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 163296, while the sum is 43.
The spelling of 11396012022763 in words is "eleven trillion, three hundred ninety-six billion, twelve million, twenty-two thousand, seven hundred sixty-three".
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