Base | Representation |
---|---|
bin | 10000100101101010100… |
… | …001000110001101010001 |
3 | 11000222102022102111112002 |
4 | 100211222201012031101 |
5 | 122134111032111023 |
6 | 2231404245243345 |
7 | 145234051656203 |
oct | 20455241061521 |
9 | 4028368374462 |
10 | 1139953394513 |
11 | 3aa4a6a776aa |
12 | 164b20103555 |
13 | 836602c050b |
14 | 3d2617c2773 |
15 | 1e9bd32db28 |
hex | 1096a846351 |
1139953394513 has 2 divisors, whose sum is σ = 1139953394514. Its totient is φ = 1139953394512.
The previous prime is 1139953394491. The next prime is 1139953394641. The reversal of 1139953394513 is 3154933599311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1061524271809 + 78429122704 = 1030303^2 + 280052^2 .
It is a cyclic number.
It is not a de Polignac number, because 1139953394513 - 216 = 1139953328977 is a prime.
It is a super-2 number, since 2×11399533945132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1139953394113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 569976697256 + 569976697257.
It is an arithmetic number, because the mean of its divisors is an integer number (569976697257).
Almost surely, 21139953394513 is an apocalyptic number.
It is an amenable number.
1139953394513 is a deficient number, since it is larger than the sum of its proper divisors (1).
1139953394513 is an equidigital number, since it uses as much as digits as its factorization.
1139953394513 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5904900, while the sum is 56.
The spelling of 1139953394513 in words is "one trillion, one hundred thirty-nine billion, nine hundred fifty-three million, three hundred ninety-four thousand, five hundred thirteen".
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